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What are the zeros of f(x)=2x^3+3x^2-9x?

2 Answers

6 votes

Answer:

x = -3, x= 0, and x = 1.5

Explanation:

The zeros of a function f(x) refers to the x-values for which f(x) = 0.

We simply graph the function and determine the points where the graph crosses the x-axis. Thus, we shall be solving the problem graphically;

From the attachment below, the graph of f(x) crosses the x-axis at;

x = -3, x= 0, and x = 1.5

What are the zeros of f(x)=2x^3+3x^2-9x?-example-1
User Michael Yin
by
6.4k points
7 votes

ANSWER


x = 0 \: or \: x = (3)/(2) \: or \: x = - 3

EXPLANATION

The given polynomial function is


f(x) =2{x}^(3) + 3 {x}^(2) - 9x

To find the zeros, we equate the function to zero.


2{x}^(3) + 3 {x}^(2) - 9x = 0

Factor x,


x(2 {x}^(2) + 3x - 9) = 0

Split the middle term,


x(2 {x}^(2) + 6x - 3x - 9) = 0


x(2x(x + 3) - 3(x + 3) = 0


x(2x - 3)(x + 3) = 0


x=0,2x-3=0,x+3=0


x = 0 \: or \: x = (3)/(2) \: or \: x = - 3

User Niall Lonergan
by
5.7k points