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What are the zeros of g(x)=(3x-1)(2x+5)(7x-14)^2

ANSWER ASAP BY THE END OF THE DAY WITH THE WORK. PLZ!

User Jackncoke
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1 Answer

4 votes

Answer:

see explanation

Explanation:

To find the zeros equate g(x) to zero, that is

(3x - 1)(2x + 5)(7x - 14)² = 0

Equate each factor to zero and solve for x

3x - 1 = 0 ⇒ 3x = 1 ⇒ x =
(1)/(3)

2x + 5 = 0 ⇒ 2x = - 5 ⇒ x = -
(5)/(2)

(7x - 14 )² = 0 ⇒ 7x - 14 = 0 ⇒ x = 2 with multiplicity 2

User Hfimy
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