Question

If Bradley has 4 times as many dimes as nickels and they have a combined value of 315 cents, how many of each coin does he have?

Answer 1

d=4n

315=5n+10d

315=5n+40n

315=45n

315/45=n

7=n

d=4n

d=4(7)

d=28

28 dimes and 7 nickels