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Derive these identities using the addition or subtraction formulas for sine or cosine:

a. sin a sin b = 1 / 2(cos(a – b) – cos(a + b))

b. sin a cos b = 1 / 2(sin(a + b) + sin(a – b))

User Apocalisp
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1 Answer

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Answer:

Explanation:

cos(a-b)-cos(a+b)=2(sina x sinb)

using formulae of cos (a-b) & cos(a+b)

cos a cos b + sina sinb - cosa cosb + sina sinb=2 sina sinb

2 sina sinb = 2 sina sinb

proved!

User Doyle
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