Question

What is the additive inverse of the complex number 13-2

Answer 1

-13 + j*2

Explanation:

The additive inverse of a complex number x = a +j*b

is a number y, such that

x + y = 0

This means that

y = -x = - a - j*b

Therefore

The additive inverse of 13 - j*2 is equal to

-(13 - j*2) = -13 +j*2