Question

An ideal gas in a closed container initially has a volume V and Temperature T the final tempera is 5/4T and the final pressure is 2P what is the final gas

Answer 1

`V_2 = (5V)/(8)`

Step-by-step explanation:

I am assuming you are saying what is the final volume of the gas

Known :

Initial volume (V1) = V

Initial temperature (T1) = T

Final temperature (T2) = 5/4 T

Initial pressure (P1) = P

Final pressure (P2) = 2P

Wanted: Final volume (V2)

`(P_1V_1)/(T_1) = (P_2V_2)/(T_2)\\(PV)/(T) = ((2P)V_2)/((5/4)T)\\(V)/(1) = ((2)V_2)/(5/4)\\5/4V = 2V_2\\\\V_2 = (5V)/(8)`