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Evaluate 10 sigma n=2 -2n-3

User Mrege
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1 Answer

4 votes

Answer:

-135

Explanation:

The summation notation of 10∑n=2 -2n-3.

We can find the values by substituting n into -2n-3.

Let's begin where n = 2

-2(2) - 3 = -7

-2(3) - 3 = -9

-2(4) - 3 = -11

-2(5) - 3 = -13

-2(6) - 3 = -15

-2(7) - 3 = -17

-2(8) - 3 = -19

-2(9) - 3 = -21

-2(10) - 3 = -23

This gives us:

-7 + -9 + -11 + -13 + -15 + -17 + -19 + -21 + -23 = -135

User Patschiboy
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