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Which shows how to find the value of this expression when x=-2 and y=5? (3x^3y^-2)^2

2 Answers

2 votes

Answer:

Explanation:

(3(-2)*3(5)*-2)^2

(-6*15*-2)^2

180^2

32,400

User Trevor Hickey
by
7.4k points
7 votes

Answer:


\Rightarrow (576)/(625)

Explanation:

Given:

Expression,
(3x^3y^(-2))^2

To find the value of expression at x=-3 and y=5

Put the values into expression


\Rightarrow (3(-2)^3(5)^(-2))^2


\Rightarrow (3\cdot -8\cdot (1)/(25))^2
\because x^(-m)=(1)/(x^m)


\Rightarrow (-(24)/(25))^2


\Rightarrow (576)/(625)

Hence, The value of expression would be
\Rightarrow (576)/(625)

User Zaak
by
7.7k points