92,191 views
32 votes
32 votes
5.18 L of nitrogen gas at 76.0°C are cooled to 6.0°C at constant pressure. Calculate the new volume of

the gas.
(write your answer in this space with sig digs and units - submit your work in the work space provided)

User Spaghettifunk
by
2.8k points

1 Answer

12 votes
12 votes

Answer:

0.409 L

Step-by-step explanation:

Because you are dealing with volume and temperature, you need to use the Charles' Law equation:

V₁ / T₁ = V₂ / T₂

In this equation, "V₁" and "T₁" represent the initial volume and temperature. "V₂" and "T₂" represent the final volume and temperature.

V₁ = 5.18 L V₂ = ? L

T₁ = 76.0 °C T₂ = 6.0 °C

V₁ / T₁ = V₂ / T₂ <----- Charles' Law equation

5.18 L / 76.0 °C = V₂ / 6.0 °C <----- Insert values

0.06815789 = V₂ / 6.0 °C <----- Simplify left side

0.409 L = V₂ <----- Multiply both sides by 6.0

User Thorsten Lorenz
by
2.4k points