Question

Given two functions j(x)=−3x+2 and k(x)=3+4x , what is the function rule for (kj) (x) ?

Answer 1

(k·j)(x) = -12x^2 -x +6

Explanation:

(k·j)(x) = k(x)·j(x) = (4x+3)(-3x+2) . . . . . substitute function definitions

= 4·(-3)x^2 +(4·2+3(-3))x +3·2 . . . . . multiply using the distributive property

= -12x^2 -x +6