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Roy has a total of 10 quarters and dimes. The value of the coins is $2.05. He has more quarters then dimes. How many of each coin does he have?​

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Answer:

7 quarters and 3 dimes

Explanation:

We know that in total, Roy has 10 quarters and dimes all together.

Here are the variables I'll be using for my equations:

q = quarters

d = dimes

q + d = 10

We also know that the valve of the coins is 2.05.

0.25q + 0.1d = 2.05

To find one variable we need to only have one variable in the equation by using the "plug in" method.

But first we need to find what q equals with this method:

q + d = 10

-d -d

Properties of inequalities states we need to subtract d from both sides of the equation.

q = 10 -d

Use the "plug in" method to "plug" this into the second equation.

0.25( 10 -d ) + 0.1d = 2.05

Solve the equation. Here is my work shown:

2.5 - 0.25d + 0.1d = 2.05

2.5 - 0.15d = 2.05

-0.15d = -0.45

d = 3

We now know that Roy has 3 dimes. We can safely come to the conclusion that Roy has 7 quarters because it states that the total amount of quarters and dimes he has is 10.

I really hopes this helps you out.

User Brendan Green
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