Answer:
29.2 m/s
Step-by-step explanation:
The escape velocity of an object from the surface of a planet is given by:
![v=\sqrt{(2GM)/(r)}](https://img.qammunity.org/2020/formulas/physics/high-school/jvvbikhuu5wr8a0jw6roagyh5xto63ngjf.png)
where
G is the gravitational constant
M is the mass of the planet
r is the radius of the planet
In this problem, we have
is the mass of the Death Star
is its radius
Substituting into the equation, we find
![v=\sqrt{(2(6.67\cdot 10^(-11) m^3 kg^(-1) s^(-2))(5.1\cdot 10^(17) kg))/(80,000 m)}=29.2 m/s](https://img.qammunity.org/2020/formulas/physics/high-school/tqhz6kwleic095epukkjp74p8lyf7mre2q.png)