Question

according to the fundamental theorem of algebra, how many zeros does the function f(x)=17x^15+41x^12+13x^3-10 have?​

Answer 1

Answer: 15

Explanation:

The total number of zeros (which includes real & complex roots) is the degree of the function. The degree of a function is the biggest exponent.

f(x) = 17x¹⁵ + 41x¹² + 13x³ - 10

has a degree of 15, so the function has 15 zeros.