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Given 4/ (-2 - cos(theta))

What is the distance between the pole and the directrix?

User Jaccar
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1 Answer

6 votes

Answer:

the distance from pole to directrix is 4 units

Explanation:

Rewritten to the form ...

r = ed/(1+e·cos(theta))

you find ..

ed = 4/-2 = -2 . . . . . where d is the distance from the pole to the directrix

e = -1/-2 = 1/2 . . . . . the eccentricity

so d = ed/e = -2/(1/2) = -4 and the ellipse has the equation ...

r = (1/2)(-4)/(1 + 1/2·cos(theta))

The directrix is a vertical line 4 units from the focus in the -x direction.

Given 4/ (-2 - cos(theta)) What is the distance between the pole and the directrix-example-1
User Maga
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