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Find the area, in square feet, of a triangle whose base is 42⁄3 feet and whose altitude is 84⁄7 feet. A. 135⁄21 B. 20 C. 40 D. 2610⁄21

2 Answers

4 votes

Answer: B. 20

Explanation:

Hi to answer this question we have to apply the next formula:

Area of a triangle: base x height (altitude) x 1/2

Replacing with the values given:

A =4 2/3 x 8 4/7 x 1/2

A= (4x3+2)/3 x (8x7+4)/7 x 1/2

A = 14/3 x 60/7 x 1/2 = 840/42=20 square feet

So, the correct option is B.20

Feel free to ask for more if needed or if you did not understand something.

User Takumi
by
5.1k points
2 votes

Answer:

Option B.
20\ ft^(2)

Explanation:

we know that

The area of a triangle is equal to


A=(1)/(2)bh

we have


b=4(2)/(3)\ ft


h=8(4)/(7)\ ft

Convert mixed numbers to an improper fractions


b=4(2)/(3)\ ft=(4*3+2)/(3)=(14)/(3)\ ft


h=8(4)/(7)\ ft=(8*7+4)/(7)=(60)/(7)\ ft

substitute the values


A=(1)/(2)((14)/(3))((60)/(7))\\ \\A=(14*60)/(2*3*7)\\ \\A=(840)/(42) \\ \\A=20\ ft^(2)

User Wildplasser
by
4.7k points