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What is the value of b and the missing symbol in Jamilla’s inequality?

What is the value of b and the missing symbol in Jamilla’s inequality?-example-1
User Vcs
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2 Answers

5 votes

Answer:

The answer for my question was also C..

Explanation:

User Michael Khalili
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3 votes

Answer:


b=1, \geq

Explanation:

we know that

The absolute value function has two solutions

Observing the graph

the solutions are


x\geq 1 and
x\leq -3

First solution (case positive)

assume the symbol of the first solution and then compare the results


\left|x+b\right|\ge2


(x+b)\ge2


x\ge2-b


2-b=1\\b=2-1\\ b=1

Second solution (case negative)


-(x+b)\ge2

Multiply by -1 both sides


(x+b)\leq-2

substitute the value of b and compare the results


(x+1)\leq-2


x\leq-2-1


x\leq-3 -------> is correct

User Lehermj
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