Question

I really need to understand this question! Please answer

Answer 1

- 3

Explanation:

Using the law of logarithms

`log_(b)` x = n ⇔ x =
`b^(n)`

let
`log_(b)`(
`(1)/(b^3)`) = n

`log_(b)`(
`b^(-3)`) = n, then

`b^(-3)` =
`b^(n)`

Since bases are the same on both sides then equate the exponents

⇒ n = - 3 → (4)