234k views
2 votes
the 6th term of an AP -5 and the 10th term is 21 find the sum of the first 30th term. please I need with a solving ​

User BonCodigo
by
6.3k points

1 Answer

4 votes

Answer:

1702.5

Explanation:

The n th term of an arithmetic progression is


a_(n) = a + (n - 1)d

where a is the first term and d the common difference, hence

a + 5d = - 5 → (1) and

a + 9d = 21 → (2)

Subtract (1) from (2) term by term

4d = 26 ( divide both sides by 4 )

d =
(26)/(4) = 6.5 ← common difference

Substitute d = 6.5 into (1 )

a + 32.5 = - 5 ( subtract 32.5 from both sides )

a = - 37.5 ← first term

The sum to n terms of an arithmetic progression is


S_(n) =
(n)/(2)[ 2a + (n - 1)d ], hence


S_(30) = 15 [ - 75 + (29 × 6.5) ]

= 15 [ - 75 + 188.5 ]

= 15 × 113.5

= 1702.5

User Shreck Ye
by
5.4k points