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The number of girl child per family was recorded for 1000 families with 3 children. The data obtained was as follows: [2] Number of Girls 0 1 2 3 Number of Families 112 314 382 192 Suppose a family is chosen at random, find the probability that it has: (a). At most one girl (b). More girls than boys

1 Answer

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Answer:


a.\ Probability = 0.426


b.\ Probability = 0.574

Explanation:

Given


Total\ Families = 1000

Number of Girls : 0 ----> 1 -----> 2 ------->3

Number of Families: 112 -> 314 --> 382 ---> 192

Solving (a): At most one girl

From the table, the number of families with at most one girl is: 112 + 314

i.e.

Number of Girls : 0 ----> 1

Number of Families: 112 -> 314

So, we have:


At\ Most\ One\ Girl = 112 + 314


At\ Most\ One\ Girl = 426

The probability is then calculated as:


Probability = (At\ Most\ One\ Girl)/(Total)


Probability = (426)/(1000)


Probability = 0.426

Solving (b): More girls

From the table, the number of families with more girl is: 382 + 192

i.e.

Number of Girls : -----> 2 ------->3

Number of Families: --> 382 ---> 192

So, we have:


More\ Girls = 382 + 192


More\ Girls = 574

The probability is then calculated as:


Probability = (More\ Girls)/(Total)


Probability = (574)/(1000)


Probability = 0.574

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