122k views
5 votes
10 points all wrong answers will be reported and explain Solve using linear combinations show your work.

10 points all wrong answers will be reported and explain Solve using linear combinations-example-1
User Moethata
by
4.9k points

1 Answer

5 votes

Answer:

x = -5, y = 4, z = 3

Explanation:

(1) 3x + y + 3z = -2

(2) 6x + 2y + 9z = 5

(3) -2x - y - z = 3

Step 1. Eliminate one of the variables in two of the equations

6x + 2y + 9z = 5 Subtract twice Equation (1)

6x + 2y + 6z = -4 from Equation (2)

3z = 9

z = 3

Step 2. Set up two new equations in two variables

3x + y + 9 = -2 Substitute z

-2x - y - 3 = 3 into (1) and (3)

(4) 3x + y = -11 Add Equations

(5) -2x - y = 6 (4) and (5)

x = -5

Step 3. Substitute x and z into one of the original equations

Substitute into (3)

-2(-5) - y - 3 = 3

10 - y - 3 = 3

7 - y = 3

- y = -4

y = 4

The solutions are x = -5, y = 4, z = 3.

Check:

(1) 3(-5) + 4 + 3(3) = -2

-15 + 4 + 9 = -2

-2 = -2

(2) 6(-5) + 2(4) + 9(3) = 5

-30 + 8 + 27 = 5

5 = 5

(3) -2(-5) - 4 - 3 = 3

10 - 4 - 3 = 3

3 = 3

User Roizpi
by
5.2k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.