Question

The specific heat of ice is 0.5 calories/gram. 60 grams of ice will require _____ calories to raise the temperature 1°C. 0.5 30 60 120

Answer 1

30 calories.........................................

Step-by-step explanation:

Answer 2

Hello!

The answer is: 30 calories

Why?

From the statement we have:

`SpecificHeat=0.5(calories)/(gram)\\\\Mass=60g\\\\AT=TemperatureChange=1 C (degree Celsius)`

We can calculate heat transferred using the following equation;

q=mCΔT

Where:

q=HeatTransferred

m=mass=60g

C=SpecificHeat=0.5\frac{calories}{g}

ΔT=TemperatureChange=1°C

So, by substituting we have:

`q=60g*0.5(calories)/(g)*1=30calories`

So, 60 grams of ice will require 30 calories to raise the temperature 1°C

Have a nice day!