Question

Which of the following equations illustrates the law of conservation of matter?

(PLEASE HELP NEED ANSWER ASAP)

Answer 1

Equation 'D' does.

If you count carefully, you'll find 4 Aluminum atoms and 6 Oxygen atoms on EACH SIDE of the equation. So matter hasn't been created or destroyed by the process; it's just been re-arranged.

Answer 2

Step-by-step explanation:

The law of conservation of matter states that the in chemical reaction the total mass on the left side of the equation should be equal to the total mass on the right side of the equation i.e. total mass on the both sides of the equation must be equal.

Option (1)

`2Al+3O_2\rightarrow Al_2O_3`

Molar mass of reactant -
`2* (26.98\ g/mol)+6* (16\ g/mol)=149.96\ g/mol`

Molar mass of product -
`2* (26.98\ g/mol)+3* (16\ g/mol)=101.96\ g/mol`

LHS ≠ RHS

Law of conservation of matter not followed

Option (2)

`4Al+O_2\rightarrow2Al_2O_3`

Molar mass of reactant -
`4* (26.98\ g/mol)+2* (16\ g/mol)=139.92\ g/mol`

Molar mass of product -
`4* (26.98\ g/mol)+6* (16\ g/mol)=203.92\ g/mol`

The law of conservation of matter is not followed.

Option (3)

`2Al+O_2\rightarrow Al_2O_3`

Molar mass of reactant -
`2* (26.98\ g/mol)+2* (16\ g/mol)=85.96\ g/mol`

Molar mass of product -
`2* (26.98\ g/mol)+3* (16\ g/mol)=101.96\ g/mol`

The law of conservation of matter is not followed.

Option (4)

`4Al+3O_2\rightarrow 2Al_2O_3`

Molar mass of reactant -
`4* (26.98\ g/mol)+6* (16\ g/mol)=203.92\ g/mol`

Molar mass of product -
`4* (26.98\ g/mol)+6* (16\ g/mol)=203.92\ g/mol`

LHS = RHS

The law of conservation of matter is followed. Hence, the correct option is (D).