Answer:
(b) 27°
(c) 34°
( ) 27°
Explanation:
Angle relations involving lines, parallel lines, and triangles come into play here.
- angles of a linear pair total 180°
- angles of a triangle total 180°
- vertical angles are congruent
- corresponding angles at a transversal crossing parallel lines are congruent
(b)
The interior angles at W and Y will be the supplement of the exterior angles at those points. The sum of interior angles is 180°.
(180° -6x) +90° +(180° -4x) = 180°
270° = 10x . . . . . . . . . add 10x and simplify
27° = x
(c)
The vertical angles at S are congruent. This tells us ...
3x +∠PSQ = 4x
∠PSQ = x
The sum of angles in triangle PSQ is 180°, so we have ...
x +x +(180° -68°) = 180°
2x = 68° . . . . . . . . add 60°-180°
x = 34° . . . . . . . . . divide by 2
( )
Angles BAD and EDF are corresponding angles, hence congruent. The sum of angles in triangle BAD is 180°.
2x +2x +72° = 180°
4x = 108° . . . . . . subtract 72°
x = 27° . . . . . . . . divide by 4