![S(O)/(H) C(A)/(H) T(O)/(A)](https://img.qammunity.org/2020/formulas/mathematics/high-school/mck38j9bg4y5ppopt65sv8hq9j6z2c7b94.png)
![Sin=(Opposite)/(Hypotenuse) Cos=(Adjacent)/(Hypotenuse) Tan=(Opposite)/(Adjacent)](https://img.qammunity.org/2020/formulas/mathematics/high-school/bwrrjbmvmehjt6l9eyxzfv8xt549h04vhf.png)
7) You have the opposite. You need the adjacent.
![Tan=(Opposite)/(Adjacent)](https://img.qammunity.org/2020/formulas/mathematics/high-school/dz2mqoe90nnwicrk8nvkv1fqrifw3vdh0l.png)
![Tan57=(12)/(x)](https://img.qammunity.org/2020/formulas/mathematics/high-school/a22wxrg2gcnznxtpoo8q9nycyofs7abhrd.png)
![x=(12)/(Tan57)](https://img.qammunity.org/2020/formulas/mathematics/high-school/hr3uex5hml3izkl6vlss231g7682k1x7wl.png)
x = 7.79289... =
7.8
8) You have the hypotenuse. You need the Opposite.
![Sin=(x)/(Hypotenuse)](https://img.qammunity.org/2020/formulas/mathematics/high-school/gw2d1ge9aszy0obb0j12wbp2413u6uuwfv.png)
![Sin37=(x)/(13)](https://img.qammunity.org/2020/formulas/mathematics/high-school/vezs9moa71bstnlvgdelnakgx4thtbx74v.png)
x = sin37 × 13
x = 7.8235... =
7.8
9) You have the hypotenuse. You need the opposite.
![Sin=(x)/(Hypotenuse)](https://img.qammunity.org/2020/formulas/mathematics/high-school/gw2d1ge9aszy0obb0j12wbp2413u6uuwfv.png)
![Sin59=(x)/(11)](https://img.qammunity.org/2020/formulas/mathematics/high-school/qpryvstfa8yjugta87hst5kwrm99r59om1.png)
x = sin59 × 11
x = 9.4288.... =
9.4
10) You have the hypotenuse. You need the opposite.
![Sin=(x)/(Hypotenuse)](https://img.qammunity.org/2020/formulas/mathematics/high-school/gw2d1ge9aszy0obb0j12wbp2413u6uuwfv.png)
![Sin53=(x)/(11)](https://img.qammunity.org/2020/formulas/mathematics/high-school/iw585h9l8mopvs8dxq2pubkye154gjnbnc.png)
x = sin53 × 11
x = 8.7459.... =
8.7