Answer:
1.62 L.
Step-by-step explanation:
- To solve these problems, we can use the general law of ideal gas: PV = nRT.
where, P is the pressure of the gas in atm (P = 101.3 kPa/101.325 ≅ 1.0 atm) .
V is the volume of the gas in L (V = ??? L).
n is the no. of moles of the gas in mol.
R is the general gas constant (R = 0.082 L.atm/mol.K),
T is the temperature of the gas in K (T = 34.0 °C + 273.15 = 307.15 K).
The volume of the gas = nRT/P.
P = 1.0 atm, V = ??? L, R = 0.082 L.atm/mol.K, n = mass/molar mass = (1.8 g)/(28.0 g/mol) = 0.0642 mol.
∴ V = nRT/P = (0.0642 mol)(0.082 L.atm/mol.K)(307.15 K)/(1.0 atm) = 1.62 L.