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What is the vertex for y=2(x+3)^2-6

1 Answer

1 vote

Answer:

(- 3, - 6)

Explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

y = 2(x + 3)² - 6 ← is in vertex form

with (h, k) = (- 3, - 6 ) ← vertex

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