Question

Pls pls pls helppp
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Answer 1

y = 4x^2 + 8x - 12

4(x^2 + 2x - 3) = 0

4(x - 1)(x + 3) = 0

x = 1, -3

Answer 2

`\fbox {x-intercepts : (1, 0) and (-3, 0)}`

`\fbox {Roots : x = 1, x = -3}`

Explanation:

Given :

• y = 4x² + 8x - 12

4 cancels throughout.

• y = x² + 2x - 4

Solving by quadratic formula :

• x = -8 ± √(8)² - 4(4)(-12) / 8
• x = -8 ± √64 + 192 / 8
• x = -8 ± √256 / 8
• x = -8 ± 16 / 8
• x = -1 ± 2
• x = 1 and x = -3

∴ Hence, the x-intercepts are (1, 0) and (-3, 0). The roots of the equation are 1 and -3.