Answer:
The friction force is 250 N
Step-by-step explanation:
The desk is moving at constant velocity. This means that its acceleration is zero: a = 0. Newton's second law states that the resultant of the forces acting on the desk is equal to the product between mass (m) and acceleration (a):
![\sum F=ma](https://img.qammunity.org/2020/formulas/physics/middle-school/fkwzgr331jt8uw70z64ozpk487u1jkdly0.png)
In this case, we know that the acceleration is zero: a = 0, so also the resultant of the forces must be zero:
(1)
We are only interested in the forces acting along the horizontal direction, since it is the direction of motion. There are two forces acting in this direction:
- the pull, forward, F = 250 N
- the friction force, backward,
![F_f](https://img.qammunity.org/2020/formulas/physics/middle-school/smwaips6k5hmzkqa6784ipfzia90wvtjb5.png)
Given (1), we have
![F-F_f = 0](https://img.qammunity.org/2020/formulas/physics/middle-school/dgm8brlv41vx7evp7aw0sbymvj7q7h4mlj.png)
So the force of friction must be equal to the pull:
![F=F_f = 250 N](https://img.qammunity.org/2020/formulas/physics/middle-school/qkjsx505ipsotr8fsv0nxefyo88giqrlru.png)