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If you pull horizontally on a desk with a force of 150 N and the desk doesn't move, the friction force must be 150 N. Now if you pull with 250 N so the desk slides at constant velocity, the friction force is

User Vps
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Answer:

The friction force is 250 N

Step-by-step explanation:

The desk is moving at constant velocity. This means that its acceleration is zero: a = 0. Newton's second law states that the resultant of the forces acting on the desk is equal to the product between mass (m) and acceleration (a):


\sum F=ma

In this case, we know that the acceleration is zero: a = 0, so also the resultant of the forces must be zero:


\sum F = 0 (1)

We are only interested in the forces acting along the horizontal direction, since it is the direction of motion. There are two forces acting in this direction:

- the pull, forward, F = 250 N

- the friction force, backward,
F_f

Given (1), we have


F-F_f = 0

So the force of friction must be equal to the pull:


F=F_f = 250 N

User Howard Hinnant
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