Question

Please help ASAP!

Use (f/g)x
f(x)=6x^2+36
g(x)=6x^2+34x-12
Show your work please!

Answer 1

`(3)/(3x-1)`

Explanation:

`(f(x))/(g(x))\\(6x^2+36)/(6x^2+34x-12)\\(6(x^2+6))/(2(3x^2+17x-6))`Factor out a 6 from the numerator and 2 from the denominator

`(3(x^2+6))/(3x^2+17x-6)` 2 in the denominator divides the 6 in the numerator

`(3(x+6))/((3x-1)(x+6))` factor the denominator, let me know if you need help with this

`(3)/(3x-1)` the (x+6)s cancel