Question

A gas in a container with a fixed volume was originally at a pressure of 316 kPa and a temperature of 154 K

What is the new pressure in atm if the temperature is increased to 235 K?​

Answer 1

482.2 kPa.

Step-by-step explanation:

• Gay-Lussac's law states that for a given mass and constant volume of an ideal gas, the pressure exerted on the sides of its container is directly proportional to its absolute temperature.

∵ P α T.

∴ P₁T₂ = P₂T₁.

P₁ = 316.0 kPa, T₁ = 154.0 K.

P₂ = ??? kPa, T₂ = 235.0 K.

∴ P₂ = (P₁T₂)/T₁ = (316.0 kPa)(235.0 K)/(154.0 K) = 482.2 kPa.