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Yuval Roth · Answer 1 · 2020-03-23T12:04:05+0000

$216 + x = x(x {}^(2) - 5) + 6x$

$216 + x = x {}^(3) - 5x + 6x$

Add like terms

$216 + x = x {}^(3) + x$

Subtract x form both sides and they both cancel out

$216 = x {}^(3)$

Subtract 216 from both sides

$216 - x {}^(3) = 0$

Plug in your calculator, in your "y=" and look at your zeros and *check if they equal each other by substituting x with the zeros and that ones that work is your answer.

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