Answer:
Let f(x) = x^2 + -8x + 19 what is the minimum value of the function? Enter your answer in the box?
Find the x-value the minimum occurs at. Use this value to find the minimum value.
(4,3)
Function Template
ax^2 + bx + c
x^2 + -8x + 19
Max/Min Point Template
- (b / 2a)
- (-8 / 2 * 1)
- (-8 / 2)
- (-4)
4
Substitute the value into the function.
(x) = x^2 + -8x + 19
f(4) = 4^2 + -8(4) + 19
f(4) = 16 + (-32) + 19
f(4) = 3
Minimum point = (4,3)
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