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What mass of oxygen reacts during the incomplete combustion of 18.0 g of propane?

What mass of oxygen reacts during the incomplete combustion of 18.0 g of propane?-example-1
User Alan Bowen
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1 Answer

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14 votes

Answer:

45.82 gm O2

Step-by-step explanation:

From your balanced equation in the first part, you can see that 2 moles propane need 7 moles O2

Find the number of moles of propane in 18 gm

mole wt of propane = ~ 12 * 3 + 8 *1 = 44 gm/mole

18 gm / 44 gm/mole = 9/22 gm/mole propane

we need 7/2 of this as O2 moles 7/2 * 9/22 = 1.432moles of O2

O2 mole weight =~ 32

1.432 moles * 32 gm/mole = 45.82 gm O2

User Varela
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