Question

Write an equation of the circle given its center and radius

Answer 1

(x-2)²+(y-3)² = 0.25

Explanation:

We have given that

Center = (2,3) ; Diameter = 1

We have to find the equation of circle.

The equation of circle is :

(x-h)²+(y-k)² = r² where (h,k) is the center of circle and r is the radius.

d = r/2

d = 1/2 = 0.5

(h,k) = (2,3)

Putting values in above equation, we have

(x-2)²+(y-3)² = (0.5)²

(x-2)²+(y-3)² = 0.25 which is equation of circle.

Answer 2

`(x-2)^2+(y-3)^2=0.25.`

Explanation:

If the center of the circle is (2,3) and the diameter of the circle is 1, then the radius is
`(1)/(2).`

The equation of the circle with center
`(x_0,y_0)` and radius r is

`(x-x_0)^2+(y-y_0)^2=r^2.`

In your case, the equation is

`(x-2)^2+(y-3)^2=0.25.`