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*ASAP* 1/2x-1>5 what’s the inequality

User Kutyel
by
6.0k points

1 Answer

4 votes


\bold{Answer}


\boxed{\bold{(5x-3)/(2x-1)<0}}


\bold{Explanation}


  • \bold{Solve: \ (1)/(2x-1)>5}


\bold{---------------------}


  • \bold{Subtract \ 5 \ From \ Both \ Sides}


\bold{(1)/(2x-1)-5>5-5}


  • \bold{Simplify}


\bold{(1)/(2x-1)-5>0}


  • \bold{Simplify \ (1)/(2x-1)-5: \ (-10x+6)/(2x-1)>0}


\bold{(-10x+6)/(2x-1)>0}


  • \bold{Factor \ (-10x+6)/(2x-1): \ (-2\left(5x-3\right))/(2x-1)>0}


\bold{(-2\left(5x-3\right))/(2x-1)>0}


  • \bold{Multiply \ Both \ Sides \ By \ -1 \ (Reverse \ Inequality)}


\bold{(\left(-2\left(5x-3\right)\right)\left(-1\right))/(2x-1)<0\cdot \left(-1\right)}


  • \bold{Simplify}


\bold{(2\left(5x-3\right))/(2x-1)<0}


  • \bold{Divide \ Both \ Sides \ By \ 2}


\bold{((2\left(5x-3\right))/(2x-1))/(2)<(0)/(2)}


  • \bold{Simplify}


\bold{(5x-3)/(2x-1)<0}


\boxed{\bold{Eclipsed}}

User Torsten
by
6.4k points