Answer:
The answer is -67.68 kJ
Step-by-step explanation:
-67.8 kJ
2NO₂(g) ⇌ N₂(g) + 2O₂(g)
ΔH°f/kJ·mol⁻¹: +33.9 0 0
ΔH°r = ΣΔH°f(products) - ΣΔH°f(reactants)
= 0 - 2(33.9)
= -67.8 kJ
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