Question

What charge, in units of milliCoulombs, is stored when a voltage of 9.6 V is applied across a 34 mF capacitor?

Answer 1

326.4 mC

Step-by-step explanation:

The relationship between charge, capacitance and voltage in a capacitor is given by

`C=(Q)/(V)`

where

C is the capacitance

Q is the charge

V is the voltage

In this problem, we have

C = 34 mF is the capacitance

V = 9.6 V is the voltage

Re-arranging the equation and substituting the numbers, we find the charge stored in the capacitor:

`Q=CV=(34 mF)(9.6 V)=326.4 mC`