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A sample of gas has a temperature of 25 oc and a volume of 122 ml. if the volume is decreased to 50 ml, what is the new temperature?

User Svth
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1 Answer

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25 votes

Answer:

10.2 °C

Step-by-step explanation:

If all other variables are held constant, you can find the new temperature using the Charles' Law equation. The equation looks like this:

V₁ / T₁ = V₂ / T₂

In this equation, "V₁" and "T₁" represent the initial volume and temperature. "V₂" and "T₂" represent the final volume and temperature. You can find the new temperature by plugging the given values into the equation and simplifying.

V₁ = 122 mL V₂ = 50 mL

T₁ = 25 °C T₂ = ? °C

V₁ / T₁ = V₂ / T₂ <----- Charles' Law equation

122 mL / 25 °C = 50 mL / T₂ <----- Insert values

4.88 = 50 mL / T₂ <----- Divide 25 from 122

4.88 x T₂ = 50 mL <----- Multiply both sides by T₂

T₂ = 10.2 °C <----- Divide both sides by 4.88

User Lasean
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