Question

A 50.0-kg child stands at the rim of a merry-go-round of radius 2.25 m, rotating with an angular speed of 3.30 rad/s.. What is the child's centripetal acceleration?

Answer 1

Answer: the child's centripetal acceleration=24.50 m/s²

Step-by-step explanation:

Given that mass of child= 50 kg

radius of merry go round= 2.25m

angular speed = 3.30 rad/s

Centripetal Acceleration = v²/ r

But V= ωr

So Centripetal Acceleration = v²/ r = (ωr)²/ r

=(3.30)² x (2.25)²/ 2.25 = (3.30)² x 2.25

=24.5025m/s²

=24.50 m/s²