Question

66th term of arithmetic sequence 4, 13, 22, 31? ​

Answer 1

`a_(66)` = 589

Explanation:

We are given the following arithmetic sequence and we are to find it 66th term:

4, 13, 22, 31

We know the formula for the arithmetic sequence which is:

`a_n=a_1(n-1)d`

where
`n` is the number of the term,

`a_1` is the first term; and

`d` is the difference between two terms.

Substituting the given values in the above formula to get:

`a_(66)=4+(66-1)9`

`a_(66)=4+(65)9`

`a_(66)=4+585`

`a_(66)=589`

Answer 2

The 66th term of given sequence is 589.

Explanation:

We have given a arithmetic sequence.

4,13,22,31

We have to find 66th term of given sequence.

The formula to find nth term of the arithmetic sequence:

aₙ = a₁+(n-1)d where d is the common difference.

d = 13-4 = 9

Putting n = 66,a₁ = 4 and d = 9 in given formula, we have

a₆₆ = 4+(66-1)(9)

a₆₆ = 4+(65)9

a₆₆ = 4+585

a₆₆ = 589 which is the answer.