Question

the motion of a 12kg object is opposed by a 30N force of friction. at what rate does friction slow the object down​

Answer 1

The rate at which the friction slows down the object is
`2.5 ms^(-2)`

Explanation:

Mass of the object = 12 kg

Opposing Force of friction = F = 30 N

The rate at which the friction slows down the object is actually the deceleration produced by that force.

According to Newton's law:

F = ma

So the acceleration/deceleration produced by a Force F on an object of mass m is a, given by:

a = F/m

Hence deceleration produced by friction = a = 30/12

`a = 2.5 ms^(-2)`