Question

If u=<-4,8> and v=<-7,5>, v-5u= ? and ||v-5u|| is approximately?

Answer 1

Explanation:

a) Given:

u=
`\:<\:-4,8\:>`

v=<-7,5>

v-5u=<-7,5>-5<-4,8>

v-5u=<-7,5>+<20,-40>

v-5u=<-7+20,5-40>

v-5u=<13,-35>

b)

The magnitude of this vector is

||v-5u||=
`√(13^2+(-35)^2)`

||v-5u||=
`√(169+1225)`

||v-5u||=
`√(1394)`

||v-5u||=
`37.3units` to the nearest tenth