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If the area of a rectangle is 4x^2*20x+16 and the side length is 2x+8 what is the width

1 Answer

4 votes

Answer: 3.965

A=16x•20x+16

A=320x/320+16/320=.05

2x+8=.05

-8 -8

2x=-7.95=-3.975

2 2

0.05

+3.975

3.965 = w final answer

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