Question

Select the two values of x that are roots of this equation 2x-3=-5x^2

Answer 1

x=3/5 and x=-1

Explanation:

a p e x

Answer 2

`\bold{Answer}`

`\boxed{\bold{X \ = \ -1, \ X \ = \ (3)/(5) }}`

`\bold{Explanation}`

• 
  `\bold{Find \ Two \ Values \ Of \ X: \ 2x-3=-5x^2}`

`\bold{-------------------}`

• 
  `\bold{Switch \ Sides}`

`\bold{-5x^2=2x-3}`

• 
  `\bold{Add \ 3 \ To \ Both \ Sides}`

`\bold{-5x^2+3=2x-3+3}`

• 
  `\bold{Simplify}`

`\bold{-5x^2+3=2x}`

• 
  `\bold{Subtract \ 2x \ From \ Both \ Sides}`

`\bold{-5x^2+3-2x=2x-2x}`

• 
  `\bold{Simplify}`

`\bold{-5x^2-2x+3=0}`

• 
  `\bold{Solve \ With \ The \ Quadratic \ Formula}`
• 
  `\bold{For \ The \ Quadratic \ Form \ For \ ax^2+bx+c=0 \ The \ Solutions \ Are \ x_(1,\:2)=(-b\pm √(b^2-4ac))/(2a)}`
• 
  `\bold{For \ A \ =-5,\:b=-2,\:c=3:\quad x_(1,\:2)=(-\left(-2\right)\pm √(\left(-2\right)^2-4\left(-5\right)3))/(2\left(-5\right))}`

`\bold{(-\left(-2\right)+√(\left(-2\right)^2-4\left(-5\right)\cdot \:3))/(2\left(-5\right)): \ -1}`

`\bold{(-\left(-2\right)-√(\left(-2\right)^2-4\left(-5\right)\cdot \:3))/(2\left(-5\right)): \ (3)/(5) }`

• 
  `\bold{Solutions}`

`\bold{x=-1,\:x=(3)/(5)}`

`\boxed{\bold{Eclipsed}}`