Question

The bottom portion of a loading bin is cone shaped. The base radius of this part of the bin is 3.5 feet and the slant height is 6.5 feet. What is the capacity and lateral surface area of this part of the bin? Round your answer to the nearest hundredth. Lateral Surface Area = sq. ft. Volume = cu. ft.

Answer 1

`\bf \textit{lateral surface of a cone}\\\\ LA=\pi r√(r^2+h^2)~~ \begin{cases} ~~ r=radius\\ sh=\stackrel{slant~height}{√(r^2+h^2)}\\[-0.5em] \hrulefill\\ r=3.5\\ sh=6.5 \end{cases}\\\\\\ LA=\pi (3.5)(6.5)\implies LA\approx71.47 \\\\[-0.35em] ~\dotfill\\\\ \stackrel{sh}{6.5}=√(r^2+h^2)\implies 6.5=√(3.5^2+h^2)\implies 6.5^2=3.5^2+h^2 \\\\\\ 6.5^2-3.5^2=h^2\implies √(6.5^2-3.5^2)=h\implies √(30)=h \\\\[-0.35em] ~\dotfill`

`\bf \textit{volume of a cone}\\\\ V=\cfrac{\pi r^2h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=3.5\\ h=√(30) \end{cases}\implies V=\cfrac{\pi (3.5)^2√(30)}{3}\implies V\approx 70.26`

Answer 2

Answer to Q1:

A = 71.47 sq.ft

Explanation:

We have given the base radius and the slant height of the cone.

base radius = r = 3.5 feet and slant height = √r²+ h² = 6.5 feet

We have to find the lateral surface area of the cone.

The formula to find the lateral surface area of the cone:

A = πr√r²+h²

Putting values in above formula, we have

A = π(3.5)(6.3)

A = 71.47 sq.ft which is the answer.

Answer to Q2:

V = 70.26 cubic ft

Explanation:

We have given the base radius and the slant height of the cone.

base radius = r = 3.5 feet and slant height = √r²+h² = 6.5 feet

We have to find the volume of the cone.

The formula to find the lateral surface area of the cone:

V = πr²h / 3

√r²+h² = 6.5

√3.5²+h² = 6.5

h = √30

Putting values in above formula, we have

V = π(3.5)²(√30) / 3

V = π (12.25)√30 / 3

V = 70.26 cubic ft which is the answer.