Answer:
11.69 kJ of heat is absorbed when 35 g of ice melts with a heat of fusion of 334 J/g in a calorimeter
Step-by-step explanation:
The amount of heat absorbed when a substance changes phase can be calculated by multiplying the mass of the substance by the heat of fusion. In this case:
Heat absorbed = mass x heat of fusion
Heat absorbed = 35 g x 334 J/g
Heat absorbed = 11,690 J
Converting to kilojoules (kJ):
Heat absorbed = 11,690 J รท 1000
Heat absorbed = 11.69 kJ