Question

50 PTS ANSWER ALL <3333333

Answer 1

hello

Explanation:

Answer 2

QUESTION 33

The length of the legs of the right triangle are given as,

6 centimeters and 8 centimeters.

The length of the hypotenuse can be found using the Pythagoras Theorem.

`{h}^(2) = {6}^(2) + {8}^(2)`

`{h}^(2) = 36+ 64`

`{h}^(2) = 100`

`h = √(100)`

`h = 10cm`

Answer: C

QUESTION 34

The triangle has a hypotenuse of length, 55 inches and a leg of 33 inches.

The length of the other leg can be found using the Pythagoras Theorem,

`{l}^(2) + {33}^(2) = {55}^(2)`

`{l}^(2) = {55}^(2) - {33}^(2)`

`{l}^(2) = 1936`

`l = √(1936)`

`l = 44cm`

Answer:B

QUESTION 35.

We want to find the distance between,

(2,-1) and (-1,3).

Recall the distance formula,

`d=√((x_2-x_1)^2+(y_2-y_1)^2)`

Substitute the values to get,

`d=√(( - 1-2)^2+(3- - 1)^2)`

`d=√(( - 3)^2+(4)^2)`

`d=√(9+16)`

`d=√(25)`

`d = 5`

Answer: 5 units.

QUESTION 36

We want to find the distance between,

(2,2) and (-3,-3).

We use the distance formula again,

`d=√(( - 3-2)^2+( - 3- 2)^2)`

`d=√(( - 5)^2+( - 5)^2)`

`d=√(25+25)`

`d=√(50)`

`d=5√(2)`

Answer: D