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What is the coefficient of the second term of the tribomial (3x+3)^2=9x^2+bc+9

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B=

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Answer:

18

Explanation:

To find the second term of the coefficient, multiply out the left hand side of the equation.


(3x+ 3)^2 = 9x^2 + bc + 9


(3x+3)(3x+3)\\9x^2 + 9x + 9x + 9\\9x^ 2+ 18x + 9

The value of b is 18.

User David Velasquez
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