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PLEASE HELP

FILL IN THE MISSING

Given: D is the midpoint of segment BF, segment BC || segment EF


Prove: ΔBDC ≅ ΔFDE

PLEASE HELP FILL IN THE MISSING Given: D is the midpoint of segment BF, segment BC-example-1

1 Answer

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Answer:

ΔBDC ≅ ΔFDE

Explanation:

The proof is given below

To prove ΔBDC ≅ ΔFDE

Statements reasons

1). BC║EF - Given

2). D is the mid point - Given

3). BD = DF - Definition of midpoint

4). <BDC = <FDE - Vertically opposite angles are equal

5). <CBD = <DFE - alternate interior angles of parallel lines are

congruent

6). ΔBDC ≅ ΔFDE ASA rule

Therefore ΔBDC ≅ ΔFDE. Hence the proof.

User Anupam Haldkar
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