Question

Identify an equation in point-alope form for the line perpendicular to y-x-7 that passes through (-2,-6).​

Answer 1

`y + 6 = -1(x + 2).`

Explanation:

Let's find the general equation of the given line:

`y - x - 7 = 0\\\\y = x + 7.`

We can see that
`m = 1.`

Thus, the slope of any perpendicular line to the line
`y = x + 7` is
`-1.`

Given that the perpendicular line passes through (-2, -6), its point-slope form equation is as given:

`y - y_1 = m(x - x_1)\\\\y - (-6) = -1(x - (-2))\\\\y + 6 = -1(x + 2).`